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身份證字號的認証規則

2007-10-10 @ 22:24 in 一般

第一位為英文字母
第二個數字是男女生之分,男生為 1,女生為 2
 
身份證字號後面八個數字之中,前面七個可以隨便打
最後一位為檢查碼,必須經過之前一個字母與8個數字的組合計算後得出
 
檢查碼的運算原則:
 
英文代號以下表轉換成數字
A=10 台北市 J=18 新竹縣 S=26 高雄縣
B=11 台中市 K=19 苗栗縣 T=27 屏東縣
C=12 基隆市 L=20 台中縣 U=28 花蓮縣
D=13 台南市 M=21 南投縣 V=29 台東縣
E=14 高雄市 N=22 彰化縣 W=32 金門縣
F=15 台北縣 O=35 新竹市 X=30 澎湖縣
G=16 宜蘭縣 P=23 雲林縣 Y=31 陽明山
H=17 桃園縣 Q=24 嘉義縣 Z=33 連江縣
I=34 嘉義市 R=25 台南縣
 
(1)英文轉成的數字, 個位數乘9再加上十位數
(2)各數字從右到左依次乘1、2、3、4....8
 
(1)與(2)的和,除10求出餘數
用10減該餘數,結果就是檢查碼,若餘數為0,檢查碼就是 0。
 
例如: 身份證號碼是 Z12345678?
 
Z 1 2 3 4 5 6 7 8 
    3 3
X X X X X X X X X X
1 9 8 7 6 5 4 3 2 1 
 ─────────────────────
3 + 27 + 8 + 14 + 18 + 20 + 20 + 18 +14 + 8 = 150
150/10=15....0 (餘數)
10-0=10 (檢查碼為0)
∴身份證字號為Z123456780
 
參考自: http://www.javaworld.com.tw/jute/post/view?bid=35&id=33999&sty=3 

迴響

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